Android EditText getText always return the first text?

The other day, I had this weird bug on my Android project. I couldn't find some helpful information on the Internet. I decided to make a post about this weird bug. First, I create an EditText variable and initialize it in OnCreate(). 
       

//...
private EditText search_bar;

protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_class_list);
    search_bar = (EditText) findViewById(R.id.search_bar);
    generate_class_list(db);
}

// I think I can get the latest value of the editText in the onClick method
// But it turned out I can't get the updated value. 
// No matter how I change the text in the editText, it always gives me the first value
public void onClick_to_search (View view) {
    search_bar = (EditText) findViewById(R.id.search_bar);
    String keyword = search_bar.getText().toString().trim().toLowerCase();
}
It make me really confused in the beginning. After half an hour of debugging, I realized that it might be the problem of the initialization. I initialized the variable in the onClick method. Problem solved. Yay! 
       

//...
//private EditText search_bar;

protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_class_list);
    //search_bar = (EditText) findViewById(R.id.search_bar);
    generate_class_list(db);
}


public void onClick_to_search (View view) {
    EditText search_bar = (EditText) findViewById(R.id.search_bar);
    String keyword = search_bar.getText().toString().trim().toLowerCase();
}
Conclusion: I entered value in editText after the completion of onCreate() method. So that means I could not get the updated value. That's why I should put the variable inside the onClick method.

Comments

Post a Comment

Popular posts from this blog

Can I name a method with the same name of the class in Java?

Can a class have a method with the same name of the class in Java? The answer is yes. See the example below. Public class MyClass { public MyClass() { } public void MyClass() { System.out.println("I have the same name as the class!"); } } You could definitely name a method with the name of the class. As a rule of thumb, you should not capitalize the first letter of the name of your method, though.
Read more

What is new in Java 8

1.  There are default methods and static methods in interfaces in Java 8. 2. Lamdas   Collections . sort ( list , ( o1 , o2 ) -> o1 . getTime () - o2 . getTime ()); Pre-Java8 Collections . sort ( list , new Comparator < Message >() { @Override public int compare ( Message o1 , Message o2 ) { return o1 . getTime () - o2 . getTime (); } });
Read more

Quicksort Java implementation

import java.util.Arrays; public class QuickSort { int [] data ; public void quicksort( int [] nums) { if (nums == null || nums. length == 0 ) return ; data = nums; sort( 0 , nums. length - 1 ); } private void sort( int left, int right) { if (right <= left) return ; int pivot = partition(left, right); sort(left, pivot - 1 ); sort(pivot + 1 , right); } /** * put all the numbers that are smaller than pivot to the left * **/ int partition( int left, int right) { int pivot = data [right]; int startIndex = left; for ( int i = left; i < right; i++) { //all the nums on the left of startIndex are smaller than pivot //the number at startIndex is >= pivot if ( data [i] < pivot) { swap(startIndex++, i); } } // put the pivot to the right position swap(startIndex, right); r...
Read more